Find 4 consecutive odd integers whose sum is 232

4 consecutive odd integers ...

x, x + 2, x + 4, x + 6

(x) + (x + 2) + (x + 4) + (x + 6) = 232

4x + 12 = 232

4x = 232 - 12

4x = 220

x = 220/4

x = 55

x + 2 = 55 + 2 = 57

x + 4 = 55 + 4 = 59

x + 6 = 55 + 6 = 61

so ur numbers are : 55, 57, 59, 61