Ask Question
28 October, 02:10

27. What is the logarithmic form of the equation e2x ≈ 1732?

ln 1732 = 2x

log2x1732 = e

2 logxe = 1732

ln 2x = 1732

+1
Answers (2)
  1. 28 October, 02:42
    0
    The answer in the first choice
  2. 28 October, 04:32
    0
    To get rid of exponential, you need to put ln on the other side.

    So, to get 2x you need to write ln 1732

    Answer is the first one.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “27. What is the logarithmic form of the equation e2x ≈ 1732? ln 1732 = 2x log2x1732 = e 2 logxe = 1732 ln 2x = 1732 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers