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17 December, 04:56

A boy has 11 coins in dimes and quarters. Their value is $1.70. How many of each does he have? Which of the following equations could be used to solve the problem? x + (11 - x) = 1.70. 25x + 10 (11 - x) = 1.70. 0.10x + 0.25 (11 - x) = 1.70

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  1. 17 December, 05:28
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    X - number of dimes, y - number of quarters

    x + y = 11

    0.10 x + 0.25 y = 1.70

    0.10 x + 0.25 (11 - x) = 1.70

    We can solve it:

    0.10 x + 2.75 x - 0.25 x = 1.70

    0.15 x = 1.05

    x = 1.05 : 0.15

    x = 7 (a boy has 7 dimes and 4 quarters)

    Answer: D) 0.10 x + 0.25 (11 - x) = 1.70
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