40% of the fish in a pond are goldfish and the rest are koi. The number of goldfish is g. The farmer then increases the number of koi by 10%. How many koi are there in the pond, in terms of g, now?

Question

Mathematics

Shepherd

27 May, 09:11

40% of the fish in a pond are goldfish and the rest are koi. The number of goldfish is g. The farmer then increases the number of koi by 10%. How many koi are there in the pond, in terms of g, now?

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Valentina Huynh · Answer 1

So 40% is goldfish

therefor 100-40=60% is koi

40%=g

koi goes up by 10%

that means 10% of the koi

10% of 60=1/10 of 60=6

60 goes up to 66

so we have

g is to 40 as is xg is to 66

g:40=xg:66

g/40=xg/66

multiply both sides by 66

66g/40=xg

divide both sides by g

66/40=x

33/20=x

there is (33/20) g koi now