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5 August, 16:06

The yard behind the Cindy's house is rectangular in shape and has a perimeter of 72 feet. If the length l of the yard is 18 feet longer than the width w of the yard, what is the area of the yard, in square feet?

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  1. 5 August, 19:09
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    Let the width of the yard be w.

    Since the length is 18feet longer, l = w + 18

    Perimeter for rectangle = 2 (l + w)

    2 (l + w) = 72

    2 (w+18 + w) = 72 Divide 2 on both sides

    (w + 18 + w) = 36

    2w + 18 = 36

    2w = 36 - 18

    2w = 18 Divide 2 on both sides

    w = 18/2

    w = 9

    Recall, length l = w + 18, l = 9 + 18 = 27

    Hence width, w = 9, length, l = 27

    Area of rectangle = l * w = 27 * 9 = 243

    Area of rectangular yard = 243 square feet.
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