To evaluate ∫ 3x2 cos (2x3 - 4) dx, it is necessary to let A. u = 6x. B. u = 6x2 C. u = 2x3 - 4 D. u = 3x2

The correct answer is C, to let u = 2x^3 - 4.

This allows du = 6x^2 dx, and the integral will become:

integral of (1/2) (du) cos (u), which can be integrated in a straightforward manner.

The rule of thumb is to set the entire expression of the trigonometric function as a single variable if possible, to make it simpler.