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8 March, 10:16

If a bridge is 1,053 feet above the Arkansas river, about how long will it take before the stone hits the water?

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  1. 8 March, 11:13
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    Assuming air resistance is negligible and a constant gravitational field.

    h (t) = 1053-16t^2 So the stone will hit the water when h (t) = 0 so

    1053-16t^2=0

    16t^2=1053

    t^2=65.8125, since t>0

    t≈8.1 seconds (to nearest tenth of a second)
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