A function is given by the equation h (x) = x 2 squared + 6x-3. what is h (3) ?

Your " h (x) = x 2 squared + 6x-3" is ambiguous. If you meant "x squared," then you need only write x^2 OR "x squared," but NOT "x 2 squared."

I will assume that by " h (x) = x 2 squared + 6x-3" you actually meant:

h (x) = x^2 + 6x-3. To find h (3), subst. 3 for x: h (3) = (3) ^2 + 6 (3) - 3, or

h (3) = 9 + 18 - 3, or h (3) = 24.