Write the first six terms of an arithmetic sequence that has 12 for the first term and 42 for the sixth term

This is an arithmetic progression.

Tn = a + (n - 1) * d.

a = First term

n = number of terms

d = common difference.

First term, a = 12.

Sixth term, T6 = a + (6 - 1) * d = a + 5d = 42

a + 5d = 42

12 + 5d = 42

5d = 42 - 12

5d = 30

d = 30/5

d = 6.

Writing the first six terms, we keep adding six.

12, 18, 24, 30, 36, 42.

Cheers.