What is 125x9 + 64y12 written as a sum of cubes?

(25x3) 3 + (4y4) 3

(5x3) 3 + (16y4) 3

(25x3) 3 + (8y4) 3

(5x3) 3 + (4y4) 3

Question

Mathematics

Averie

27 December, 08:11

What is 125x9 + 64y12 written as a sum of cubes?

(25x3) 3 + (4y4) 3

(5x3) 3 + (16y4) 3

(25x3) 3 + (8y4) 3

(5x3) 3 + (4y4) 3

+2

Answers (1)

Know the Answer?

Paige Hurst · Answer 1

The answer is (5x3) 3 + (4y4) 3

proof

(5x^3) ^3 + (4y^4) ^3=?

(5x^3) ^3=5^3. (x^3) ^3=125x^3.3 = 125x^9

(4y^4) ^3=4^3. (y^4) ^3=64y^4.3=64y12

finally 125x9 + 64y12

(5x^3) ^3 + (4y^4) ^3=

What is 125x9 + 64y12 written as a sum of cubes?(25x3) 3 + (4y4) 3(5x3) 3 + (16y4) 3(25x3) 3 + (8y4) 3(5x3) 3 + (4y4) 3

What is 125x9 + 64y12 written as a sum of cubes?

(25x3) 3 + (4y4) 3

(5x3) 3 + (16y4) 3

(25x3) 3 + (8y4) 3

(5x3) 3 + (4y4) 3