How do you factor 7x^{2}+29x+4

When you have a coefficient in front of the "x^2" value, you have to multiply it by the end value (4)

so you want a set of integers that will add up to 29, by multiple to (7 x 4) = 28

The only numbers like that are 28 and 1, they add up to 29 and multiply to 29

Therefore, rewrite it like this 7x^2 + 28x + x + 4

and then factor out the 7x in the first two terms, to get this

7x (x+4) + x + 4, then factor out 1 in the latter two terms to get this:

7x (x+4) + 1 (x+4), then use grouping to combine what you've got:

The factors are: {{ (7x+1) (x+4) }}