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Yesterday, 23:20

The rectangle shown has an area of (y^2+8y+15) m^2 what is the

width of the rectangle

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  1. Yesterday, 23:41
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    If the dimensions are "nice" factors of the quadratic, and if y > - 3, we have

    ... area = (y + 3) (y + 5)

    y+5 is greater than y + 3, so we take the width to be ...

    ... width = y+3
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