Probability theory predicts that there is 77.6% chance of a particular soccer player making 2 penalty shots in a row. If the soccer player taking 2 penalty shots is simulated 2500 times, in about how many simulations would you expect at least 1 missed shot?

Question

Bailey Crawford

22 August, 10:27

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Answers (1)

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Honey · Answer 1

P (at least 1 missed shot) = 100 - 77.6 = 22.4%

Number of times to expect al least 1 missed shot = 0.224 x 2500 = 560 times.