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12 October, 10:03

How do i solve x2 - 10x = - 21?

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  1. 12 October, 13:52
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    X^2 - 10x = - 21 (adding both sides by 21)

    x^2 - 10x + 21 = 0

    Now, we can solve for x ... first thing that we have to do is, figure out what is the value of x that could cause the equation gives us 0 (zero as the result). The value is when x = 7 and x = - 3. Then we can simply right the equation as:

    (x-7) (x+3) = 0 ... it means that:

    x-7 = 0

    x+3 = 0

    So, the solution for x is ...

    x = 7 and x = - 3
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