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25 June, 17:27

solve the system of linear equations

x + y = 4 and 2x + 3y = 0

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  1. 25 June, 20:06
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    solve this answer by using substitution. set the first equation to x=-y+4 then substitute - y+4 for x in the second equation.

    2 (-y+4) + 3y=0

    -2y+8 + 3y=0

    y+8=0

    y=-8

    now use - 8 and solve for x

    x + (-8) = 4

    x=12
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