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Mathematics
Dixie Henson
6 December, 11:41
How much is 43=y+x/3-5?
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Jeremiah Gilbert
6 December, 12:53
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1 Subtract yy y from both sides
43-y = x3 - 5 43-y=/frac{x}{3}-5 43-y = 3 x - 5
2 Add 55 5 to both sides
43-y+5 = x3 43-y+5=/frac{x}{3} 43-y+5 = 3 x
3 Simplify 43-y+5 43-y+5 43-y+5 to 48-y 48-y 48-y
48-y = x3 48-y=/frac{x}{3} 48-y = 3 x
4 Multiply both sides by 33 3
(48-y) * 3=x (48-y) / times 3=x (48-y) * 3=x
5 Regroup terms
3 (48-y) = x 3 (48-y) = x 3 (48-y) = x
6 Switch sides
x=3 (48-y) x=3 (48-y) x=3 (48-y)
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