Ask Question
1 September, 19:31

X-y+z=-1

x+y+3z=-1

2x-y+2z=0

+3
Answers (1)
  1. 1 September, 22:49
    0
    1x - 1y + 1z = - 1 ⇒ 1x - 1y + 1z = - 1

    1x + 1y + 3z = - 1 ⇒ 1x + 1y + 3z = - 1

    2x - 1y + 2z = 0 ⇒ 2x + 4z = - 2

    1x - 1y + 1z = - 1 ⇒ 1x + 1y + 3z = - 1

    1x + 1y + 3z = - 1 ⇒ 2x - 1y + 2z = 0

    2x - 1y + 2z = 0 ⇒ 3x + 5z = - 1

    2x + 4z = - 2 ⇒ 10x + 20z = - 10

    3x + 5z = - 1 ⇒ 12x + 20z = - 4

    -2x = - 6

    -2 - 2

    x = 3

    2x + 4z = - 2

    2 (3) + 4z = - 2

    6 + 4z = - 2

    - 6 - 6

    4z = - 8

    4 4

    z = - 2

    x - y + z = - 1

    3 - y + (-2) = - 1

    3 - y - 2 = - 1

    3 - 2 - y = - 1

    1 - y = - 1

    - 1 - 1

    -y = - 2

    -1 - 1

    y = 2

    (x, y, z) = (3, 2, - 2)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “X-y+z=-1 x+y+3z=-1 2x-y+2z=0 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers