Let f (x) = x + 8 and g (x) = x2 - 6x - 7. Find f (g (2)).

F (x) = x + 8

g (x) = x² - 6x - 7

f (g (2)) = ((2) ² - 6 (2) - 7) + 8

f (g (2)) = (4 - 12 - 7) + 8

f (g (2)) = (-8 - 7) + 8

f (g (2)) = - 15 + 8

f (g (2)) = - 7

Mathematical Work:

f (x) = x+8

g (x) = x2-6x-7

f (g (2)) = (2^2-6 (2) - 7) + 8

f (g (2)) = (4-12-7) + 8

f (g (2)) = - 7

Explanation:

f (x) = x+8

g (x) = x2-6x-7

f (g (2)) = ?

2 was given as the x for function g and when you substitute 2 into function g's equation (g (2) = (2^2-6 (2) - 7) = - 15, you would get - 15. The answer to function g would be the x for function f. Which would be f (-15) = - 15+8 and the answer for f (g (2)) is - 7.