F (x) = x^2-8x+16 x and y intercepts and vertex

So in graphing form F (x) = y so

y=x^2-8x+16

so x intercept is when the line passes through the x axis or when y=0

y intercept is when the line passes throught the y axis or when x=0

x intercept

0=x^2-8x+16

factor

what 2 number multiply to 16 and add to get - 8

the numbers are - 4 an d - 4

0 = (x-4) (x-4)

set them to zero

x-4=0

add 4

x=4

x intercept=4 or (4,0)

y intercept

y=x^2-8x+16

x=0

y=0^2-8 (0) + 16

y=0+16

y=16

y intercept=16 or (0,16)

x intercept is 4 (4,0)

y intercetp is 16 (0,16)