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20 February, 16:24

Old macdonald looked out his window and saw some cows and chickens. there were a total of 28 animals and 74 legs. assuming that all the cows have 4 legs, and all the chickens have 2 legs, how many of each animal did old mcdonald see

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  1. 20 February, 17:34
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    For word problems, assign variables so you can express them into equations. For this problem, the unknown is the number of each animals. Let's assign x to the number of cows and y to the number of chickens. It is mentioned that there are a total of 28 animals. Therefore, we can formulate the first independent equation to be

    x + y = 28 - - - > eqn 1

    Next, we know that the total number of legs are 74. Since each cow has 4 legs and each chicken has 2 legs, the second independent equation we could formulate is:

    4x + 2y = 74 - - - > eqn 2

    Now, we have a system of linear equations. There are two unknowns and two independent equations. Thus, the system is solvable. Let's use the method of substituting to solve this. Rearrange eqn 1 such that x is a function of y. Let's denote this as eqn 1'.

    x = 28 - y - - - > eqn 1'

    Substitute eqn 1' to eqn 2:

    4 (28 - y) + 2y = 74

    112 - 4y + 2y = 74

    -2y = 74 - 112

    -2y = - 38

    y = - 38/-2

    y = 19

    Therefore, there are 19 chickens. Now, we use y=19 to substitute to eqn 1:

    x + 19 = 28

    x = 28 - 19

    x = 9

    Therefore, there are 9 cows.
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