Twice one number is 20 more than another number. One fourth the first number is 2 less than one fourth the second number. Find the numbers.

Let x and y are 2 numbers

2x = 20 + y (1st equation)

1/4x = 1/4 y - 2 (2nd equation)

2x = 20 + y (1st equation)

y = 2x - 20 replace this to the 2nd equation

1/4x = 1/4 (2x-20) - 2

1/4x = 1/2x - 5 - 2

1/4x = 1/2x - 7

1/4x - 1/2x = - 7

1/4x - 2/4x = - 7

-1/4x = - 7

x = - 7 * - 4

x = 28

y = 2x - 20

y = 2 (28) - 20

y = 56 - 20

y = 36

Proof:

2x = 20 + y (1st equation)

2 (28) = 20 + 36

56 = 56

1/4x = 1/4 y - 2 (2nd equation)

1/4 (28) = 1/4 (36) - 2

7 = 9-2

7 = 7

Answer: Numbers are 28 and 36