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7 May, 18:55

Find two consecutive integers such that twice the first added to three times the second is equal to 83

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  1. 7 May, 19:26
    0
    First number - a second number - a + 2 a + a + 2 = 83 2a = 81 40.5 = 41 first number - 41 second number - 43
  2. 7 May, 22:12
    0
    Let the first number=x and the second number = x+1 so

    2 (x) + 3 (x+1) = 83 2 (16) + 3 (17) = 83

    2x+3x+3=83 32+51=83

    5x=83-3

    5x=80

    5x/5=80/5

    x=16 16+1=17

    Therefor the two consecutive integers are 16 and 17
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