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17 January, 06:02

What is the third term of (2x-1) ^5

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  1. 17 January, 09:00
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    (2x-1) ^5

    = (2x-1) ^5

    = (2x-1) * (2x-1) * (2x-1) * (2x-1)

    =32x^5 - 80x^4 + 80x^3 - 40x^2 + 10x-1
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