Prove sin^3z*cos^2z=sin^3z-sin^5z

Left hand side

sin^3z * (1 - sin^2z) = RHS

let sin z = y

y^3 * (1 - y^2) = RHS

y^3 - y^6 = RHS

sin^3z - sin^6z = RHS

the answer at RHS should be to the power of 6. u better check it next time