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30 July, 01:07

Prove sin^3z*cos^2z=sin^3z-sin^5z

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  1. 30 July, 02:15
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    Left hand side

    sin^3z * (1 - sin^2z) = RHS

    let sin z = y

    y^3 * (1 - y^2) = RHS

    y^3 - y^6 = RHS

    sin^3z - sin^6z = RHS

    the answer at RHS should be to the power of 6. u better check it next time
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