Find the sum of the sequence 37+38+39+40 + ... 130

The sum is of37+38+39+40 + ... 130 is 154.13

First, you have to calculate the number in the sequence

an = a + (n-1) d

130 = 27 + (n-1) 1

130-27 = n-1

103+1 = n

n = 104

Now, calculating for sum (Sn)

Sn = n/2 (a+an) = 104/2 (37+130) = 52 (167) = 8684