The length of each side of a square is 3 inches more than the length of each side of a smaller square. The sum of the areas of the squares is 149^2. Find the lengths of the sides of the two squares

The length of each side of a square is 3in more than the length of each side of a smaller square.

let the length of smaller square=x

the length of big square=x+3

The sum of the areas of the squares is 149in^2.

so x^2 + (x+3) ^2=149

or x^2+x^2+6x+9=149

or 2x^2+6x=149-9=140