Ask Question
23 September, 07:28

The manager of a baseball team has 15 players to choose from for his nine person batting order. How many different ways can he arrange the players in the lineup. A. 5005. B. 362880. C. 3603600. D. 1816214400

+1
Answers (1)
  1. 23 September, 10:11
    0
    This is 15P9 Number of permutations of 9 in 15.

    = 15! / (15-9) !

    = 1816214400
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The manager of a baseball team has 15 players to choose from for his nine person batting order. How many different ways can he arrange the ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers