Use the Law of Sines to solve (if possible) the triangle. If two solutions exist, find both. Round your answers to two decimal places.

A = 119 degrees, a = 128, b = 106

(sin119) / 128=sinB/106

sinB=106 (sin119) / 128

B=arcsin (106 (sin119) / 128)

B≈46.41°

C≈ (180-119-46.41) = 14.59°

(sin119) / 128 = (sin14.59) / c

c=128 (sin14.59) / sin119

c≈36.87

So the sides a, b, c are 128, 106, 36.87 respectively and

angles a, b, c are 119°, 46.41°, 14.69° respectively.