A man and his three children spent $40 to attend a show. A second family of three children and their two parents spent $53 for the same show. How much does each child's ticket cost?

Here is the answer to the given problem above.

Let x be the number of parents and y for the children.

x + 3y = 40

2x + 3y = 53

x = 40 - 3y

2 (40-3y) + 3y = 53

80 - 6y + 3y = 53

80 - 3y = 53

-3y = 53 - 80

-3y = - 27 (divide both sides by - 3)

y = 9

This means that the cost per child is $9

Now solve for x

x = 40 - 3y

x = 40 - 3 (9)

x = 40 - 27

x = 13

So the cost per parent is $13.

Hope this answers your question.