Ask Question
13 May, 03:59

Prove this (sinx-tanx) (cosx-cotx) = (sinx-1) (cosx-1)

+2
Answers (2)
  1. 13 May, 06:25
    0
    (sinx - tanx) (cosx - cotx)

    = (sinx - sinx cosx) (cosx - cosx sinx)

    = sinx (1 - 1 cosx) cosx (1 - 1 sinx)

    = sinx (cosx cosx - 1 cosx) cosx (sinx sinx - 1 sinx)

    = sinx cosx (cosx - 1) cosx sinx (sinx - 1)

    = (cosx - 1) (sinx - 1)
  2. 13 May, 06:51
    0
    Distribute first

    sinx cosx - sinx cotx - cosx tanx+tanx cotx

    sinx cosx - sinx (cosx/sinx) - cosx (sinx/cosx) + tanx (cosx/sinx)

    sinxcosx - cosx - sinx + 1

    and factor

    cosx (sinx - 1) - 1 (sinx - 1)

    (sinx - 1) (cosx-1)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Prove this (sinx-tanx) (cosx-cotx) = (sinx-1) (cosx-1) ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers