Solve on the interval [0, 2Pi):

1 + cos (theta) = (sqrt (3) + 2) / 2

A. Pi/6, 5Pi/6

B. Pi/3, 5Pi/3

C. Pi/6, 11Pi/6

D. 7Pi/6, 11Pi/6

Question

Gabriela Bell

5 November, 06:49

+3

Answers (1)

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Mariah · Answer 1

1 + cos t = (√3 + 2) / 2

cos t = (√3 + 2) / 2 - 1

cos t = (√3 + 2 - 2) / 2

cos t = √3/2

t 1 = π/6, t 2 = 11π/6

Answer: C) π/6, 11π/6.

Solve on the interval [0, 2Pi):1 + cos (theta) = (sqrt (3) + 2) / 2A. Pi/6, 5Pi/6B. Pi/3, 5Pi/3C. Pi/6, 11Pi/6D. 7Pi/6, 11Pi/6