Ask Question
5 November, 06:49

Solve on the interval [0, 2Pi):

1 + cos (theta) = (sqrt (3) + 2) / 2

A. Pi/6, 5Pi/6

B. Pi/3, 5Pi/3

C. Pi/6, 11Pi/6

D. 7Pi/6, 11Pi/6

+3
Answers (1)
  1. 5 November, 09:03
    0
    1 + cos t = (√3 + 2) / 2

    cos t = (√3 + 2) / 2 - 1

    cos t = (√3 + 2 - 2) / 2

    cos t = √3/2

    t 1 = π/6, t 2 = 11π/6

    Answer: C) π/6, 11π/6.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Solve on the interval [0, 2Pi): 1 + cos (theta) = (sqrt (3) + 2) / 2 A. Pi/6, 5Pi/6 B. Pi/3, 5Pi/3 C. Pi/6, 11Pi/6 D. 7Pi/6, 11Pi/6 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers