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28 August, 07:20

The base of a triangle is twice its hypotenuse, the sine of the angle opposite to its base is

a) Ö3/2, b) 1, c) 1/2, d) Ö3

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  1. 28 August, 10:38
    0
    The answer b = 2h

    the angle opposite to its base is a

    so sina = b/2h = b/b=1

    the answer is b) 1
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