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4 January, 10:32

Write a quadratic equation in standard form with roots - 2 and - 5

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  1. 4 January, 11:43
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    To solve this problem. First lets work our way backwards and try to figure out the binomials that will result in these roots.

    -2 root = X int = - 2

    Thus it would be (X + 2) because if you solve for x the solution or X intercept is - 2.

    Same thing for - 5.

    (X+5).

    Next place them together and multiply or foil to obtain the quadratic.

    Y = (X+5) (X+2)

    Y = X^2 + 7x + 10

    Standard form = Ax^2 + / - Bx + / - C = 0.

    The standard form is X^2 + 7x + 10.
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