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23 January, 18:30

g (x) = x3 + 6x2 + 12x + 8 Determine the function's value when x = - 1. g (-1) = - 3 g (-1) = 0 g (-1) = 1 g (-1) = 27

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  1. 23 January, 21:50
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    The correct answer is that g (-1) = 1.

    To do this problem, we have to plug in - 1 for x and evaluate the expression.

    g (-1) = x^3 + 6x^2 + 12x + 8

    (-1) ^3 + 6 (-1) ^2 + 12 (-1) + 8

    -1 + 6 - 12 + 8

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