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18 August, 08:58

Jim, Carla and Tommy are members of the same family. Carla is 5 years older than Jim. Tommy is 6 years older than Carla. The sum of their three ages is 31 years. How old is each one them?

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Answers (2)
  1. 18 August, 09:15
    0
    So,

    We'll solve it with only one placeholder, since that's simpler.

    Jim's age = J

    Carla's age = C

    Tommy's age = T

    J = base

    Carla's age = J + 5

    Tommy's age = Carla's age + 6 or J + 5 + 6 or J + 11

    Sum of ages = 31

    (J) + (J + 5) + (J + 11) = 31

    3J + 16 = 31

    Subtract 16 from both sides

    3J = 15

    Divide both sides by 3

    J = 5

    Carla's age = J + 5

    Carla's age = 10

    Tommy's age = Carla's age + 6

    Tommy's age = 10 + 6 or 16

    5 + 10 + 16 = 31

    15 + 16 = 31

    31 = 31 This checks.

    Jim is 5.

    Carla is 10.

    Tommy is 16.
  2. 18 August, 12:24
    0
    Lets

    Jim x years old

    Carla (x+5) years old

    Tommy (x+5) + 6 years old

    sum is x + (x+5) + (x+5) + 6=31 years old

    3x+16=31

    3x=15

    x=5 - age of Jim

    x+5=5+5=10 - age of Carla

    x+5+6=16 - age of Tommy

    Answer: 5, 10 and 16 y. o
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