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25 September, 05:57

Factor completely: 2x3 + 14x2 + 6x + 42

2[ (x2 + 3) (x + 7) ]

(2x2 + 6) (x + 7)

(x2 + 3) (2x + 14)

2 (x3 + 7x2 + 3x + 21)

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Answers (1)
  1. 25 September, 08:24
    0
    To factor all you do is ...

    Factor 2 x3 + 14 x2 + 6x + 42 2 x3 + 14 x2 + 6x + 42 = 2 (x+7) (x2 + 3) Answer: 2 (x+7) (x2 + 3)
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