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27 August, 11:08

Y = sec θ tan θ differentiate

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Answers (1)
  1. 27 August, 13:16
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    Y = sec (θ) tan (θ).

    Solution:

    We use here the product rule that is

    (fg) 0 = f 0 g + fg0.

    So

    y 0 = (sec (θ) tan (θ)) tan (θ) + sec (θ) tan2 (θ)

    = sec (θ) (tan2 (θ) + sec2 (θ)).
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