I need 2 cones with different dimensions but the same volume

Cone Volume = (π • r² • h) : 3

radius = 4

height = 24

Cone Volume = (PI * 4*4*24) / 3

Cone Volume = 402.12

If we reduce the height by 4 (from 24 to 6) then we have to increase the radius by 2 (from 4 to 8) because the radius is squared.

Cone Volume = (PI * 8*8*6) / 3

Cone Volume = 402.12