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Mathematics
Raine
4 February, 19:56
How to factor 64x^4 + xy^3
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Amelia Vaughan
4 February, 21:30
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You factor out an x and get
x (64x^3+y^3)
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Marlon Dunn
4 February, 21:52
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So we kkonw that 64=4^3
so if we factor out x we get
x (4^3 (x^3) + y^3) or x[ (4x) ^3+y^3)
so the additon of two perfect cubes so
(4x+y) (16x^2+4xy+y^2)
and we remember that this is all times x so
x[ (4x+y (16^2+4xy+y^2)) ]
or (x) (4x+y) (16x^2+4xy+y^2)
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