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31 January, 15:46

an = cos (npi/2). If convergent find limit of sequence?

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  1. 31 January, 18:19
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    The sequence is: cos (π/2), cos (π), cos (3π/2), cos (2π), ...

    or: 0,-1,0,1,0,-1,0,1, ... Since cos (nπ/2) oscillates between - 1 and 1 as n tends to infinity, this sequence is divergent (limit does not exist).
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