What is the vertex of g (x) = 8x2 - 64x? (4, - 128) (-4, - 128) (4, - 16) (-4, - 16)

The answer is (4, - 128). If the function is written in the form y = a (x - h) ^2 + k, the vertex will be (h, k). Let's write the function 8x^2 - 64x in the form of a (x - h) ^2 + k. g (x) = 8x^2 - 64x. g (x) = 8 * x^2 - 8 * 8x. g (x) = 8 (x^2 - 8x). g (x) = 8 (x^2 - 8x + 16 - 16). g (x) = 8 ((x^2 - 8x + 16) - 16). g (x) = 8 ((x - 4) ^2 - 16). g (x) = 8 (x - 4) ^2 - 8 * 16. g (x) = 8 (x - 4) ^2 - 128. The function is now in the form a (x - h) ^2 + k, where a = 8, h = 4, and k = - 128. Thus, the vertex is (4, - 128).