Find the value of the expression (4x-12) + (12xy-10) (4x-12) + (12xy-10) for x=4 and y=6

(4x-12) + (12xy-10) (4x-12) + (12xy-10) = 4x-12 + 12.4. x. x. y - 12.12. xy - 10.4. x + 10.12 + 12xy - 10

= 4x - 10 + 48 (x^2) y - 144xy - 40x + 120 + 12xy - 10

= 48yx^2 + 4x - 40x - 144xy + 12xy - 10+120-10

= 48yx^2 - 36x - 132xy + 100

For x = 4 and y = 6

(4x-12) + (12xy-10) (4x-12) + (12xy-10) = 48yx^2 - 36x - 132xy + 100

= 48.6. (4^2) - 36.4 - 132.4.6 + 100

= 4608 - 144 - 3168 + 100

= 1396