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26 August, 02:52

A shopowner blends three types of tea, A, B, Cbin the ratio 6:4:7. If the mass of tea C in the mixture is 28kg, find the difference in the masses of the other two types of tea

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  1. 26 August, 04:33
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    7:28 = 4:b = 6:a

    you can notice that you multiply 7 by 4 to get 28, so you multiply 4 by 4 to get b and 6 by 4 to get a. or you can say that 7/28 = 4/b and 7/28 = 6/a and solve it the normal way.

    b=4*4=16

    a=6*4=24

    24-16 = 8
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