Find the derivative of the function ... y = cot2 (sin θ).

Question

Reginald Thornton

20 February, 22:00

+5

Answers (2)

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Lizbeth Eaton · Answer 1

Y' = 2 cot (sin t) * derivative of cot (sint t)

2 cot (sin t) * [ - cosec^2 (sin t) ] * derivative of sin t

-2 cot (sin t) cosec^2 (sin t) * cos t

Darwin Hunt · Answer 2

Y = cot2 (sinФ)

dy/dФ = d/dФcot2 (sinФ)

dy/dФ = - cosec²2 (sinФ) d/dФ2 (sinФ)

dy/dФ = - cosec²2 (sinФ) 2cosФ

dy/dФ = - 2[cosФ][cosec²2 (sinФ) ]