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20 February, 22:00

Find the derivative of the function ... y = cot2 (sin θ).

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Answers (2)
  1. 20 February, 22:55
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    Y' = 2 cot (sin t) * derivative of cot (sint t)

    2 cot (sin t) * [ - cosec^2 (sin t) ] * derivative of sin t

    -2 cot (sin t) cosec^2 (sin t) * cos t
  2. 21 February, 00:29
    0
    Y = cot2 (sinФ)

    dy/dФ = d/dФcot2 (sinФ)

    dy/dФ = - cosec²2 (sinФ) d/dФ2 (sinФ)

    dy/dФ = - cosec²2 (sinФ) 2cosФ

    dy/dФ = - 2[cosФ][cosec²2 (sinФ) ]
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