How do I solve this system of equations by substitution?

y - 3x = 2, y = (x + 1) ^2 - 5

Hello,

y-3x=2==>x = (y-2) / 3

==> (x+1) ² = ((y-2) / 3+1) ² = (y+1) ²/9

y = (x+1) ²-5

==>y = (y²+2y1) / 9 - 5

==>y²-7y-44=0; Δ=7²+4*44=225=15²

==>y = (7+15) / 2 or y = (7-15) / 2

==>y = 11 and x = (11-2) / 3=3

or y=-4 and x = (-4-2) / 3=-2

sol={ (3,11); (-2,-4) }