Which exponential function has an initial value of 2? f (x) = 2 (3x) orf (x) = 3 (2x) or neither

Question

Mathematics

Terry Benton

6 December, 12:39

Which exponential function has an initial value of 2? f (x) = 2 (3x) orf (x) = 3 (2x) or neither

+2

Answers (2)

Know the Answer?

Seth Rangel · Answer 1

F (x) = 3 (2x) is the answer in e2020, because the funciton has a value of 2 and 2+1 = 3 so that gives you 3 (2x)

Lozano · Answer 2

The correct answer is A, C cannot be correct because f (x) = 3 (2ˣ) would be in the parenthesis. For A, f (x) = 2 (3ˣ) it's in the right spot since it's asking for the exponential function.