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16 August, 08:28

Find the exact solutions of sin (2x) - sin (x) = 0 in the interval [0, 2pi)

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  1. 16 August, 08:58
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    Sin (2x) - sin (x) = 0

    2sin (x) * cos (x) - sin (x) = 0

    sin (x) * (2cos (x) - 1) = 0

    Sin (x) = 0 = > x [PiK]

    Cos (x) = 1/2 = > x[Pi/3 + (2PiK/3)

    K=0 x=0

    K=1 x=Pi

    K=2 x=5Pi/3

    So the answer is 0, Pi, 5Pi/3
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