Which inequality models the problem?

The length of a rectangle is twice its width. The perimeter of the rectangle is less than 50 meters, what is the greatest width of the rectangle?

2 (2w) + 2 (w) < 50

2w < 50

2 + 2w < 50

2w x 2 < 50

Question

Gracie Odonnell

15 January, 03:38

+2

Answers (1)

Know the Answer?

Ava Powers · Answer 1

L is 2w

l=2w

p is less than 50

P<50

so

P=2L+2W

2L+2W<50

2 (2w) + 2 (w) <50

first one

Which inequality models the problem?The length of a rectangle is twice its width. The perimeter of the rectangle is less than 50 meters, what is the greatest width of the rectangle?2 (2w) + 2 (w) < 502w < 502 + 2w < 502w x 2 < 50