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15 January, 03:38

Which inequality models the problem?

The length of a rectangle is twice its width. The perimeter of the rectangle is less than 50 meters, what is the greatest width of the rectangle?

2 (2w) + 2 (w) < 50

2w < 50

2 + 2w < 50

2w x 2 < 50

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Answers (1)
  1. 15 January, 06:46
    0
    L is 2w

    l=2w

    p is less than 50

    P<50

    so

    P=2L+2W

    2L+2W<50

    2 (2w) + 2 (w) <50

    first one
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