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1 November, 05:42

Which equation is y=6x^2+12-10 rewritten in vertex form

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  1. 1 November, 08:41
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    The formula in order to obtain the vertex form of a quadratic equation is given as

    y=a (x-h) ^2+k where (h, k) is the vertex of the quadratic equation which is parabolic in shape and it is opening upward.

    As given in the problem, y=6x^2+12x-10

    Using the formula, we can transformed the quadratic equation y=6x^2+12x-10 into its vertex form:

    y=6x^2+12x-10

    y = (6x^2+12x) - 10 (grouping)

    y=6 (x^2+2x) - 10 (factoring Common terms per group)

    y=6 (x^2+2x+1) - 10-6 (Completing the squares)

    y=6 (x+1) ^2-16 (Factor and Simplify)

    Hence, the vertex form of y = 6x^2+12x-10 is y=6 (x+1) ^2-16
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