2. The equation h (t) = - 16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.

What is the initial velocity when the rock is thrown?

For this case we have an equation of the form:

h (t) = - (1/2) * a * t ^ 2 + vo * t + h0

Where,

vo: initial speed

a: acceleration:

h0: initial height.

We have the following equation:

h (t) = - 16t2 + 19t + 110

Therefore, the initial velocity is:

vo = 19 feet / s

Answer:

The initial velocity when the rock is thrown:

vo = 19 feet / s